Log Base 9989 of 12

What is Log Base 9989 of 12 or log9989(12)?


Log9989(12)

= 0.2698275550191

Formula How to

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How to find what is Log Base 9989 of 12? The logarithm of a number to a given base is the exponent to which the base must be raised to produce the number. In mathematical terms, if "b" is the base and "x" is the number, then the logarithm of "x" to the base "b" is written as logb(x) and is defined as the exponent "y" such that b^y = x.

The logarithm of a number to a given base is a useful tool in many areas of mathematics and science, including finance, engineering, and physics. It's also used in solving exponential equations and in graphing logarithmic functions.

In mathematics, the most common logarithms are logarithms to the base 10, which are called common logarithms, and logarithms to the base e, which are called natural logarithms. The natural logarithm is denoted by the symbol ln, and has special properties in calculus and other areas of mathematics.

To calculate any "log base of" use this fromula, which is given below-

logb(x) =
loge(x)/loge(b)
; x>0, b>1;

Where,

  • b = base;
  • x = value;

For calculation, here's how to calculate log base 9989 of 12 using the formula above, step by step instructions are given below

  1. Input the value as per formula.
    log9989(12) =
    loge(12)/loge(9989)
  2. Calculate the log value for numerator and denominator part.
    2.484906649788/9.2092397665321
  3. After simplify the fraction, you will get the result. Which is,
    0.2698275550191

logb(x) Equal to
log9989(7) 0.21129975963131
log9989(8) 0.22579947904461
log9989(9) 0.23858913797872
log9989(10) 0.25002987774974
log9989(11) 0.26037928575958
log9989(12) 0.2698275550191
log9989(13) 0.27851912019741
log9989(14) 0.28656625264618
log9989(15) 0.29405795372423
log9989(16) 0.30106597205948
log9989(17) 0.30764899338951

log9989(12) or Log Base 9989 of 12 is equal to 0.2698275550191.

loge(9989) 9.2092397665321
log10(9989) 3.9995220131289

loge(12) 2.484906649788
log10(12) 1.0791812460476