Log Base 2 of 128

What is Log Base 2 of 128 or log2(128)?


Log2(128)

= 7

Formula How to

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How to find what is Log Base 2 of 128? The logarithm of a number to a given base is the exponent to which the base must be raised to produce the number. In mathematical terms, if "b" is the base and "x" is the number, then the logarithm of "x" to the base "b" is written as logb(x) and is defined as the exponent "y" such that b^y = x.

The logarithm of a number to a given base is a useful tool in many areas of mathematics and science, including finance, engineering, and physics. It's also used in solving exponential equations and in graphing logarithmic functions.

In mathematics, the most common logarithms are logarithms to the base 10, which are called common logarithms, and logarithms to the base e, which are called natural logarithms. The natural logarithm is denoted by the symbol ln, and has special properties in calculus and other areas of mathematics.

To calculate any "log base of" use this fromula, which is given below-

logb(x) =
loge(x)/loge(b)
; x>0, b>1;

Where,

  • b = base;
  • x = value;

For calculation, here's how to calculate log base 2 of 128 using the formula above, step by step instructions are given below

  1. Input the value as per formula.
    log2(128) =
    loge(128)/loge(2)
  2. Calculate the log value for numerator and denominator part.
    4.8520302639196/0.69314718055995
  3. After simplify the fraction, you will get the result. Which is,
    7

logb(x) Equal to
log2(123) 6.9425145053392
log2(124) 6.9541963103869
log2(125) 6.9657842846621
log2(126) 6.9772799234999
log2(127) 6.9886846867722
log2(128) 7
log2(129) 7.0112272554233
log2(130) 7.0223678130285
log2(131) 7.0334230015375
log2(132) 7.0443941193585
log2(133) 7.0552824355012

log2(128) or Log Base 2 of 128 is equal to 7.

loge(2) 0.69314718055995
log10(2) 0.30102999566398

loge(128) 4.8520302639196
log10(128) 2.1072099696479